Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • In fig 4 , O is the center of circle such that diameter AB = 13 cm and AC = 12 cm . BC is joined . Find the area of the shaded region 

In fig 4 , O is the center of circle such that diameter AB = 13 cm and AC = 12 cm . BC is joined . Find the area of the shaded region 

 

 

 

 
 
 
 
 

Answers (1)

AB = 13 cm = diameter 

AC = 12 cm 

Since \angle ACB = 90 

 \Delta ABC is right-angled triangle 

AB^2 = AC^2 + BC^2 \\\\ 13 ^ 2 = 12 ^2 + BC^2 \\\\ \sqrt {13 ^ 2-12 ^2} = BC\\\\BC = \sqrt { 169 -144} = \sqrt { 25} = 5cm \\\\

Now area of shaded region = area of semicirlce - area of \Delta ABC \\\\ = \frac{\pi}{2}\times \left (\frac{d}{2} \right )^2 - 1/2 \times BC \times AC \\\\ \frac{3.14}{2}\times \frac{169 }{4}- \frac{1}{2} \times 5 \times 12 \\\\ 66.33 - 30 \\\\

Shaded area = 33.33 cm^2

 

Posted by

Ravindra Pindel

View full answer

Similar Questions

Latest Question