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In Figure 1, ABC is an isosceles triangle right angled at C with AC = 4 cm. Find the length of AB

 

 

 
 
 
 
 

Answers (1)

Given,

\DeltaABC is an isosceles triangle

Right-angled at C [\angle C = 90\degree]

AC = 4cm

AB = ?

\DeltaABC = isosceles \Rightarrow AC = BC = 4 cm

AB = \sqrt{AC^2 + BC^2}

AB = \sqrt{4^2 + 4^2}

AB = \sqrt{16+ 16}

AB = \sqrt{32}

AB = 4\sqrt{2}

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Safeer PP

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