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In how many ways can five children stand in a queue?

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Assuming that it is a linear queue and not circular queue.

Any of the 5 children can occupy the  1st position, any of the remaining 4 persons can occupy the second,  any of the remaining 3 persons can occupy the third position  and so on...

number of ways is  =  5 * 4 * 3 * 2 * 1  = 5 ! = 120

Posted by

Deependra Verma

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