# In the circuit shown in the figure, find the value of the current shown in the ammeter A. figure 1 to find the current shown in ammeter, find the current through 6 resistance. Here assume ammeter is ideal, so resistance of ammeter is is zero. The 4 resistance and 2 resisatnce are in series.

We know at series connection

parallel connection

So

The figure can be redrawn into

figure 2 and  are parallel so effective resistance is

Then figure become

figure 3 9 and 3 are in series,

effective resistance is 9  + 3  = 12

Figure become,

figure 4 12  and 12  are in parallel so,

figure 5 3 and 6  are in series, so

3 + 6 = 9

By ohm's law,

In figure 4 both 12  resistance have  current = 0.5A

The equivalent figure is, from the above diagram, the current through 6 resistance is

Hence, the current shown in the ammeter is 0.25A,

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