In the given reactionthe rate of formation of is . Calculate the(i) rate of reaction, and(ii) rate of disappearance of .

$-\Delta [A]/\Delta t = -1/3 \Delta [B]/\Delta t = 1/2 \Delta [C]/\Delta t$

(i) Rate =

= $1/2 \Delta [C]/\Delta t$

= 2.4x 10-4/2 = 1.25 x 10-4 mol l-1 s -1

(ii) rate of disappearance of  = $-\Delta [B]/\Delta t$= 3 x 1.25 x 10-4 = 3.75 x 10-4 mol l-1 s -1

Related Chapters

Preparation Products

Knockout NEET May 2023 (Easy Installments)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Mentorship from our Experts, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 5499/-
Knockout JEE Main April 2021 (One Month)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Mentorship from our Experts, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 14000/- ₹ 4999/-
Knockout NEET Aug 2021 (One Month)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Mentorship from our Experts, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 14000/- ₹ 4999/-
Knockout JEE Main May 2021

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Mentorship from our Experts, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 22999/- ₹ 9999/-
Knockout NEET Aug 2021

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Mentorship from our Experts, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 22999/- ₹ 9999/-
Boost your Preparation for JEE Main with our Foundation Course

Exams
Articles
Questions