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Integrate: sin square root x .

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Solution:  We have ,

                  I=int sinsqrtxhspace0.1cmdx

          Put ,    x^frac12=tRightarrow frac12x^1/2dx=dtRightarrow dx=2sqrtxdt=2tdt

          herefore    I=2int (tsin t)dt=2[-tcos t+sin t]+c

                I=2[-sqrtxcos sqrtx+sin sqrtx]+c.

 

                        

Posted by

Deependra Verma

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