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Let f(x) and g(x) be function which take integers as argument . Let f(x+y) =f(x)+g(y) +8 for all intergers x and y .let f(x)=x for all negative integers x and let g(8) . Find f(0)

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Solution: As , $f(x+y)=f(x)+g(y)+8$

Put $x=-8,y=8$

$herefore f(0)=f(-8)+g(8)+8\ \Rightarrow f(0)=-8+17+8=17$

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Deependra Verma

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