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Monochromatic light of frequency 6.0\times 10^{14} Hz is produced by a laser. The power emitted is 2.0\times 10^{-3}\; W. Calculate the (i) energy of a photon in the light beam and (ii) number of photons emitted on an average by the source

 

 
 
 
 
 

Answers (1)

(i) Energy of photon =h\nu

                                  =6.63\times 10^{-34}\times 6\times 10^{14}J

                                  =3.978\times 10^{-19}J

Number of the photon emitted / sec =\frac{Power}{Energy\; of\; photon}

                      =\frac{2\times 10^{-3}}{3.978\times 10^{-19}}=5.03\times 10^{15}\; Photon/sec

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Safeer PP

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