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 A long cylindrical vessel is half filled with a liquid. When the vessel is rotated about its own vertical axis, the liquid rises up near the wall. If the radius of the vessel is 5 cm and its rotational speed is 2  rotations per second, then the difference in the heights between the centre and the sides, in cm, will be :

 

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Radius of the vessel = 5 cm

Rotational speed = 2 rpm

Gravitational acceleration = 9.8 m/s2

\omega=2 \pi \times f=2 \pi \times 2=4 \pi \text { radians } / \text { second }

\begin{aligned} &h=\frac{\omega^2 r^2}{2 g}\\ &h=\frac{(4 \pi)^2 \times 5^2}{2 \times 9.8} \end{aligned}

= 201.42 cm

Posted by

Divya Sharma

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