An Unbiased coin is tossed 4 times. What is the Probability of getting (i) 3 heads

Given that an unbiased coin is tossed 4 times.

find the probability of getting 3 head

solution:

total number of events = $2^4$ =16

Number of ways of getting 3 heads = $\frac{4!}{1! 3!} = 4$

probability =4/16 =1/4

Given that an unbiased coin is tossed 4 times.

find the probability of getting 3 head

solution:

total number of events =  =16

Number of ways of getting 3 heads =

probability =4/16 =1/4

4/16=1/4

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