Nine times a two-digit number is the same as twice the number obtained by interchanging the digits of the number. If one digit of the number exceeds the other number by 7, find the number.

Answers (1)

Assume the number is ab.

ATQ

9 (10a + b) = 2(10b + a) 

88 a = 11b 

8a = b... (i)

b = a + 7 ..(ii)

By equation (i) and (ii)

7a = 7 

a = 1

b =8

Hence the required number is 18.

 

 

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