One mole of a non ideal gas undergoes a change of state(2.0 atm, 3.0 L, 95 K) to (4.0 atm, 5.0 L, 245 K) with a change in internal energy, ΔU = 30 L atm. The change in enthalpy (ΔH) of the process in L atm will be?

Answers (1)
S Sumit

We know that ,

ΔH = ΔU + Δ(PV) =  ΔU + (P2V2 - P1V1)

Putting the given values in the equation - 

      = 30.0 L atm + (4.0 atm x 5.0 L) - (2.0 atm x 3.0 L)

      = 44.0 L atm.

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