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One of the exterior angles of a triangle is 80 degrees and the interior opposite angles are in the ratio 3 :5 . find the angles of the triangle

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Sum of interior angle of opposite site = exterior angle

Given ratio of the interior angle = 3:5

So angles are  = 3x80/8 = 30 degree

Second angle = 5x80/8 = 50 degree

Third angle = 180 -30-50 = 100 degree

Posted by

Ravindra Pindel

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