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  • Period of f(x) =sin3x cos[3x]-cos3x sin[3x] (where [] denotes the greatest integer function ) is

Period of f(x) =sin3x cos[3x]-cos3x sin[3x] (where [] denotes the greatest integer function ) is

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Solution:x=x-[x] which is periodic with period 1.

Now, \ f(x)=sin(3x-[3x])=sin([3x])

3x has period 1/3

herefore f(x) has also period 1/3

Posted by

Deependra Verma

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