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  • Please Solve R.D. Sharma Class 12 Chapter 18 Indefinite Integrals Exercise Revision Exercise Question 45 Maths Textbook Solution.

Please Solve R.D. Sharma Class 12 Chapter 18 Indefinite Integrals Exercise  Revision Exercise Question 45 Maths Textbook Solution.

Answers (1)

Answer:

I=\frac{1}{6} \log \left|\frac{x-1}{x+5}\right|+c

Given:

\int \frac{1}{x^{2}+4 x-5} d x

Hint:

To solve this equation we will make whole square of the denominator.

Solution: 

\int \frac{1}{(x+2)^{2}-9} d x

  I=\int \frac{1}{(x+2)^{2}-9} d x

I=\int \frac{1}{(x+2)^{2}-9} d x

I=\int \frac{1}{(x+2)^{2}-(3)^{2}} d x

I=\int \frac{1}{2 \times 3} \log \left|\frac{x+2-3}{x+2+3}\right|+c

I=\frac{1}{6} \log \left|\frac{x-1}{x+5}\right|+c

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