Prove that (2a – 4b)(3a – 6c)=6(2b–a)(2c-a).​

Answers (1)

To Prove : (2a – 4b)(3a – 6c)=6(2b–a)(2c-a)

LHS = (2a – 4b)(3a – 6c)

        = (-2)(2b - a) (-3) (2c -a)

       = 6(2b–a)(2c-a) = RHS

Hence proved.

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