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Prove that : sin^-1 12/13 +cos^-1 4/5 + tan^-1 63/16 =pi

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Solution: We have ,

$sin^-112/13 +cos^-14/5+ an^-163/16$

$Rightarrow$ $an^-112/5+ an^-13/4+ an^-163/16$

$Rightarrow$ $= pi+ an^-1[(12/5+3/4)/(1-12/5 imes 3/4)]+ an^-163/16$

$=pi+ an^-1(-63/16)+ an^-163/16$

$Rightarrow$ $pi$

Posted by

Deependra Verma

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