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  • show me the formation of ionic compounds by transfer of electrons for Al2O3

Show the formation of ionic compounds by transfer of electrons for Al2O3.

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Step 1: Write electronic configurations

  • Aluminium (Z=13): 2,8,3 → needs to lose 3 electrons to achieve noble gas configuration.

  • Oxygen (Z=8): 2,6 → needs to gain 2 electrons to complete its octet.

Step 2: Transfer of electrons

  • Each Al atom loses 3 electrons → forms Al3+

  • Each O atom gains 2 electrons → forms O2-

Step 3: Balancing electron transfer

  • To balance, 2 Al atoms lose 6 electrons in total.

  • 3 O atoms gain 6 electrons in total.

Thus, the compound formed is Al2O3

Representation of Ionic Bond Formation

Al3+ (2,8,3) → Al3++ 3e− 

O2- (2,6) + 2e− → O2−

Now,

2Al + 3O → Al2O3

Final Answer: In Al2O3, each aluminium atom transfers its 3 valence electrons to oxygen atoms. Two Al atoms lose 6 electrons, which are gained by three O atoms. Thus, the compound is formed by electrostatic attraction between Al3+ and O2−.

Posted by

Saumya Singh

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