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Sides of a triangle are in ratio 1:root3:2, find the ratio of angles of triangles

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Let;sides;be;x,;sqrt3 x;and;2x\* Rightarrow cos C=fraca^2+b^2-c^22ab=fracx^2+3x^2-4x^22sqrt3 x^2=0\*Rightarrow cos C=0 Rightarrow angle C=90^circ\*Similarly,cos B= fraca^2+c^2-b^22ac=fracx^2+4x^2-3x^24x^2\*Rightarrow cos B=frac12 Rightarrow angle B=60^circ\*Now,angle A+angle B+angle C=180^ circ\* Rightarrow angle A+60^circ+90^circ=180^circ\* Rightarrow angle A=30^circ\* Rightarrow angle A:angle B:angle C=30:60:90\* Rightarrow angle A:angle B:angle C=1:2:3

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Deependra Verma

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