Simplify : tan^-1 (a+bx/b-ax) , x
Answers (1)

Solution: We have ,

           	an^-1(fraca+bxb-ax),x< fracba

     \ \ Rightarrow 	an^-1[fraca+bxb-ax]=	an^-1[fracfracab+x1-fracabx]\ \ Rightarrow hspace1cm=	an^-1fracab+	an^-1x

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