Simplify: tan^-1 ( acosx - bsinx /bcosx + asinx).

Answers (1)

Solution:   We have ,

                   	an^-1(fracacos x-bsin xbcos x+asin x)

             	an^-1(fracacos x-bsin xbcos x+asin x)=	an^-1(fracfracab-	an x1+fracab	an x)

   Rightarrow                  	an^-1(fracacos x-bsin xbcos x+asin x)=	an^-1fracab-	an^-1(	an x)=	an^-1fracab-x

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