Solution:
Given equation
ax^2 + bx + c = 0,Root of equation is SinA &CosA
Now
SinA + CosA = -b/a
SinA*CosA= c/a
We know Sin^2A + Cos^2A=1
( SinA + CosA)^2= Sin^2A +Cos^2A+2SinA*CosA
( -b/a )^2 =1+2c/a
b^2/a^2 =1 + 2c/a
a^2 + 2ac =b^2
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