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solve 1/x-2+2/x-1=6/x

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1/(x-2)+2/(x-1)=6/x

1(x-1)x+2(x-2)x=6(x-2)(x-1)

x^2-x+2x^2-4x=6(x^2-x-2x+2)

3x^2-5x=6x^2-18x+12

6x^2-3x^2-18x+5x+12=0

3x^2-13x+12=0

3x^2-9x-4x+12=0

3x(x-3)-4(x-3)=0

(3x-4)(x-3)=0

3x-4=0 or x-3=0

x=4/3 or x=3


Therefor, x=3 or 4/3

Posted by

Suraj Bhandari

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