solve: (9x+2)(4x^2+35x-9)=0

Answers (1)
S safeer

\\(9x+2)(4x^2+35x-9)=0\\implies\ (9x+2)=0\\that\ is \ x=\frac{-2}{9}

Also.

\\(4x^2+35x-9)=0\\\\x^2+\frac{35}{4}x-\frac{9}{4}=0\\\\x^2-\frac{1}{4}x+\frac{36}{4}x-\frac{9}{4}=0\\\\x(x-\frac{1}{4})+9(x-\frac{1}{4})=0\\\\(x-\frac{1}{4})(x+9)=0\\implies\\x=\frac{1}{4},\ x=9

So the values of x are -2/9, 1/4 and 9

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