# Solve the pair of equation 3x+2y_13=0 and 6x_4y_10=0 by ising substution methodplz tell me answer?

Solution:  The given system of equations is

$\\ 3x+2y=13 ............(1)\\ \\ 6x-4y=10 ............(2)$

Form (1) ,we get

$\\\Rightarrow 2y=13-3x$

Substituting  $\\ 2y=13-3x$  in (2) we get

$\\ \Rightarrow 6x-2(13-3x)=10 \\ \\ \Rightarrow 6x-26+6x=10\\ \\ \Rightarrow 12x=36\Rightarrow x=3$

Putting  $\\ x=3$ in  $\\ 2y=13-3x\\ \\ \Rightarrow 2y=4\Rightarrow y=2$

Hence , the solution of the given system of equation is $\\ x=3$ , $\\ y=2$

## Most Viewed Questions

### Preparation Products

##### Knockout NEET May 2023 (Easy Installments)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Mentorship from our Experts, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 5499/-
##### Knockout JEE Main April 2021 (One Month)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Mentorship from our Experts, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 14000/- ₹ 4999/-
##### Knockout NEET Aug 2021 (One Month)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Mentorship from our Experts, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 14000/- ₹ 4999/-
##### Knockout JEE Main May 2021

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Weekend Live Classes, Mentorship from our Experts, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 22999/- ₹ 9999/-