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Solve the quadratic equation by using formulae x2=36

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 x2=36

 x2- 36 =0

Here a=1, b=0, c = -36

x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\\ x = \frac{-0 \pm \sqrt{0^2-4 \times 1 \times (-36)}}{2\times 1}\\ x = \frac{ \pm \sqrt{4 \times 36}}{2\times 1}\\ x = \pm 6

Posted by

Ravindra Pindel

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