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Solve using identity 27x^3-8y^3

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 27x3-8y3 =  (3x)3-(2y)3                        { (a)3-(b)3 = (a-b)(a2 + b2 + ab) }

                = (3x-2y)((3x)2 + (2y)2 + (3x)(2y)) 

                =  (3x-2y)( 9x2 + 4y2 + 6xy)  

Posted by

Ravindra Pindel

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