Assume the a.p has first term "a" and common difference "d".
ATQ
a + 3d = 3a
2a = 3d ...(i)
a + 6d = 2(a + 2d ) +1
2a + 4d + 1 = a + 6d
a = 2d - 1 ...(ii)
Put value of a in equation (ii)
2 (2d -1) = 3d
4d - 3d = 2
d =2
a = 4-1 = 3
Hence the first tem and common difference of a.p. is 3,2 respectively.