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  • THE ANGLE OFELEVATION OF AN AEROPLANE FROM A POINT ON THE GROUND IS 60.AFTER FLYING 15SECONDS THE ANGLE OF ELEVATION CHANGES TO 30.IF THE AEROPLANE IS FLYING AT A CONSTANT HEIGHT OF 1500√3 ,FIND THE SPEED OF THE AEROPLANE

THE ANGLE OFELEVATION OF AN AEROPLANE FROM A POINT ON THE GROUND IS 60.AFTER FLYING 15SECONDS THE ANGLE OF ELEVATION CHANGES TO 30.IF THE AEROPLANE IS FLYING AT A CONSTANT HEIGHT OF 1500√3 ,FIND THE SPEED OF THE AEROPLANE

Answers (1)

From triangle ACD

\\\\tan30=\frac{CD}{AD}\\\frac{1}{\sqrt{3}}=\frac{1500\sqrt{3}}{AD}\\AD=4500m

From triangle ABE

\\\\tan60=\frac{EB}{AE}\\\sqrt{3}=\frac{1500\sqrt{3}}{AE}\\AE=1500m

The distance travelled in 15sec BC=ED=AD-AE=4500-1500=3000m

Speed=distance travelled/time=3000/15=200m/sec

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