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What is the A.P. whose nth term is 2n-1?

 

Answers (1)

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Given- The nth term of an A.P. is $$
a_{n} =2n−1
$$

To find- A.P. sequence

Solution- Here, 

  • a is the first term
  • d is the common difference
  • n is the term number

Using $$
a_{n} = 2n−1
$$

So, the first few terms by plugging in values of n is:

  1. When n = 1 $$
    a_{1} =2(1) - 1 = 1.
    $$
  2. When n = 2 $$
    a_{2} =2(2) - 1 = 3
    $$
  3. When n = 3 $$
    a_{3} =2(3) - 1 = 5
    $$

Therefore, the terms of the A.P. are: 1, 3, 5, 7, 9, ...

First term (a) = 1 and common difference (d) = 3 - 1 = 2

Posted by

Saniya Khatri

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