The area of the triangle whose vertices are A( 1,-1, 2) ,B(2,1,-1) and C(3,-1,2) is

Answers (1)

Solution:   

          Area hspace0.2cmof hspace0.2cmigtriangleup ABC=frac12left | vecBA	imes vecBC 
ight |\ \ Rightarrow hspace1cm vecBA=-i-2j+3k\ \ Rightarrow hspace1cm vecBC=i-2j+3k \ \ Rightarrow hspace1cm Area =frac12eginvmatrix i &j &k \ -1 & -2 &3 \ 1 &-2 &3 endvmatrix=frac12left | 6i+4k 
ight |=sqrt13

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