The de-Broglie wavelength associated with a proton and a neutron are found to be equal. Which of the two has a higher value of kinetic energy?

Answers (1)

As The de-Broglie wavelength is given as 

\lambda =\frac{h}{p}

where p=momentum

As given The de-Broglie wavelength associated with a proton and a neutron are found to be equal.

that means they both will have same p (momentum)

Now kinetic energy is given as

K=\frac{1}{2}mv^2=\frac{p^2}{2m}

Since for both p is same

So we can say that K \ \alpha \ \frac{1}{m}

and

mass of proton = 1.6726 x 10-27 kg
mass of neutron = 1.6749 x 10-27 kg

Therefore, since a proton has a lighter mass, it will have a higher value of kinetic energy. 

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