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  • The equation e^sinx -e^-sinx -4=0 has

The equation e^sinx -e^-sinx -4=0 has

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Solution:     we have ,   e^ sin x- e^ -sin x-4=0

                 Put ,      e^ sin x=u            .......(1)

                  herefore    The given equation becomes

                           u^2-4u-1=0Rightarrow u=2pmsqrt5

                   Either        e^ sin x=2+sqrt5             ..........(2)

                  or               e^ sin x=2-sqrt5             ..........(3)

                   (2)  and (3)  is impossible because     frac1eleq e^sin xleq e

                  herefore      the given equation has no real solution.

Posted by

Deependra Verma

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