The far point of a myopic eye is 60 cm. What is the nature and power of the lens required to correct the problem

Answers (1)
S safeer

The focal length required is

1/f = 1/v - 1/u

here u is taken as infinity and v is -60 cm because the person can see an object up to 60 cm. So a distant object is considered such that the image is formed at 60 cm

Therefore

1/f=1/(-60) - 0

f=-60 cm=-0.6 m

Power = 1/f = 1/(- 0.6)= -1.667 Diopter.

Preparation Products

JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Rank Booster NEET 2021

This course will help student to be better prepared and study in the right direction for NEET..

₹ 13999/- ₹ 9999/-
Buy Now
Knockout JEE Main April 2021 (Easy Installments)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 4999/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout NEET May 2022

An exhaustive E-learning program for the complete preparation of NEET..

₹ 34999/- ₹ 24999/-
Buy Now
Exams
Articles
Questions