The figure shows a series LCR circuit connected to a variable frequency 230 V source.

(a) Determine the source frequency which drives the circuit in resonance.

(b) Calculate the impedance of the circuit and amplitude of current at resonance.

(c) Show that potential drop across LC combination is zero at resonating frequency.

 

 
 
 
 
 

Answers (1)

(a) Determining the source frequency (w)

We know, w=\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{5\times 80\times 10^{-6}}}=\frac{1}{\sqrt{400\times 10^{-6}}}

                w=\frac{1000}{20}=50Hz

(b) Calculating the impedance of the given circuit and amplitude of current at resonance.

At resonance  Z=R=40\; \Omega

I^{max}_{m}=\frac{230\sqrt{2}}{R}=\frac{230\sqrt{2}}{40}=8.1\; A

(c) the potential drop across L and C,

At resonance 

X_{C}=X_{L}

iX_{C}=iX_{L}

implies that 

V_{C}=V_{L}

V_{C}-V_{L}=0     

Most Viewed Questions

Related Chapters

Preparation Products

Knockout CUET (Physics, Chemistry and Mathematics)

Complete Study Material based on Class 12th Syllabus, 10000+ Question Bank, Unlimited Chapter-Wise and Subject-Wise Mock Tests, Study Improvement Plan.

₹ 7999/- ₹ 4999/-
Buy Now
Knockout CUET (Physics, Chemistry and Biology)

Complete Study Material based on Class 12th Syllabus, 10000+ Question Bank, Unlimited Chapter-Wise and Subject-Wise Mock Tests, Study Improvement Plan.

₹ 7999/- ₹ 4999/-
Buy Now
Knockout JEE Main (Six Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 9999/- ₹ 8499/-
Buy Now
Knockout JEE Main (Nine Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 13999/- ₹ 12499/-
Buy Now
Knockout NEET (Six Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 9999/- ₹ 8499/-
Buy Now
Boost your Preparation for JEE Main with our Foundation Course
 
Exams
Articles
Questions