The largest interval in which the function f(x)=3sin [ square root (pi^2/16 -x^2) ]

Answers (1)

Solution:     The given function is  defined if

                       (fracpi^216-x^2)geq 0Rightarrow -fracpi4leq xleq fracpi4.

                  ecause     f(-fracpi4)=0;f(fracpi4)=0;3sin (fracpi4)=frac3sqrt2

                  	herefore         f  takes values in the interval    [0,frac3sqrt2].

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