The length of the minute hand of a clock is 6cm . Find the area swept by the minute hand during the time period 8:05 AM and 8:45 AM

Answers (1)
S safeer

Area swept in 60 minutes 

=\pi \times(length \ of \ minute\ hand)^2

Area swept in 40 min 

\\=\frac{40}{60}\times\pi \times(length \ of \ minute\ hand)^2\\\\=\frac{4}{6}\times\pi\times6^2=24\pi cm^2=75.4cm^2

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