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?The number of integral values of x which satisfies inequality | x^2+x-6| less than 6 is

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Solution:  We have ,   left | x^2+x-6 
ight |< 6

                 -6< x^2+x-6< 6\ \ Rightarrow x^2+x> 0 hspace0.2cmand hspace0.2cmx^2+x-12< 0

              	herefore       xin (-4,-1)cup (0,3).

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Deependra Verma

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