The number of real roots of the equations 10^x+10^-x=log 25 , (where base 10) is

Answers (1)

Solution:   We have ,     log_1025=10^x+10^-x

                  Rightarrow           log_1025=(10^fracx2-10^frac-x2)+2> 2

                 Rightarrow         25> 10^2  which is impossible ,

                      Therefore , the number of real roots is nil.

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