The number of Solution of the equation sin 2x =[1+sin2x]+[1-cos 2x] in [0,pi/2] where [.] is the greatest integer function is

Answers (1)

Solution:      We have  ,

                      sin 2x =[1+sin 2x]+[1-cos 2x]

                     sin 2x =1           xin [0,fracpi4]

                                   =2        xin [fracpi4,fracpi2].

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