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The period of the function f(x)=cos^3x+sin^3x is

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Solution:      f(x)=cos^3x+sin^3x

                      f(x)=frac14[3(sin x+cos x)-sin 3x+cos 3x].

            Now ,       pd(sin x)=2pi;pd(cos x)=2pi,

            pd(sin x+cos x)=2pi,pd(sin 3x)=frac2pi3 and pd(cos 3x)=frac2pi3.

       herefore                 pd(f)=LCM\frac2pi1,frac2pi3=fracLCM2pi,2piHCF1,3=2pi.

Posted by

Deependra Verma

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