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  • The ratio of mass percent of C and H of an organic compound (CxHyOz) is 6:1 . If one molecule of the above compound (CxHyOz) contains half as much oxygen as required to burn one molecule of compoun

The ratio of mass percent of C and H of an organic compound (CxHyOz) is 6:1 . If one molecule of the above compound (CxHyOz) contains half as much oxygen as required to burn one molecule of compound CxHy completely to CO2 and H2O. The empirical formula of compound CxHyOz is.

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Mass ratio C : H = 6 : 1 → Moles: C = 0.5, H = 1

So, C?H?

Combustion of C?H? needs 3 O atoms

Compound has half of that = 1.5 O atoms → z = 1.5

So: C?H?O?.?

Multiply all by 2 → C?H?O?

C?H?O?

Posted by

Divya Sharma

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