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The reaction between A and B is first order with respect to A and zero order with respect to B. For this reaction, fill in the blanks in the following table.

Experiment [A] mol/L [B] mol/L Initial rate mol/L/min
I 0.1 0.1 2.0\times 10^{-2}
II - 0.2 4.0\times 10^{-2}
III 0.4 0.4 -
IV - 0.2 2.0\times 10^{-2}

 

 

 

 

 
 
 
 
 

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Experiment [A] mol/L [B] mol/L Initial rate mol/L/min
I 0.1 0.1 2.0\times 10^{-2}
II 0.2 0.2 4.0\times 10^{-2}
III 0.4 0.4 8.0\times 10^{-2}
IV 0.1 0.2 2.0\times 10^{-2}

(II) Since the reaction is first order with respect to A, the rate of the reaction doubles by doubling the concentration.

\therefore [A]=0.2 mol/L

(III) Concentration of A changed from 0.2 to 0.4, hence, the rate of the reaction doubles concentration of B changed from 0.2 to 0.4, it does not affect the rate of the reaction.

(IV) The rate of the reaction becomes \frac{1}{4}th of the precedingone, hence the concentration of A becomes  \frac{1}{4}th irrespective of concentration of B.

 

Posted by

Sumit Saini

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