# The reaction between A and B is first order with respect to A and zero order with respect to B. For this reaction, fill in the blanks in the following table. Experiment [A] mol/L [B] mol/L Initial rate mol/L/min I 0.1 0.1 $2.0\times 10^{-2}$ II - 0.2 $4.0\times 10^{-2}$ III 0.4 0.4 - IV - 0.2 $2.0\times 10^{-2}$

 Experiment [A] mol/L [B] mol/L Initial rate mol/L/min I 0.1 0.1 $2.0\times 10^{-2}$ II 0.2 0.2 $4.0\times 10^{-2}$ III 0.4 0.4 $8.0\times 10^{-2}$ IV 0.1 0.2 $2.0\times 10^{-2}$

(II) Since the reaction is first order with respect to A, the rate of the reaction doubles by doubling the concentration.

$\therefore [A]=0.2 mol/L$

(III) Concentration of A changed from 0.2 to 0.4, hence, the rate of the reaction doubles concentration of B changed from 0.2 to 0.4, it does not affect the rate of the reaction.

(IV) The rate of the reaction becomes $\frac{1}{4}th$ of the precedingone, hence the concentration of A becomes  $\frac{1}{4}th$ irrespective of concentration of B.

## Related Chapters

### Preparation Products

##### Knockout NEET July 2020

An exhaustive E-learning program for the complete preparation of NEET..

₹ 15999/- ₹ 6999/-
##### Rank Booster NEET 2020

This course will help student to be better prepared and study in the right direction for NEET..

₹ 9999/- ₹ 4999/-
##### Knockout JEE Main July 2020

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 12999/- ₹ 6999/-
##### Test Series NEET July 2020

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 4999/- ₹ 2999/-