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The set of real numbers of a such that a^2+2a , 2a+3 , a^2+3a+8 are the sides of a triangle , is

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Solution:   Sum of two sides   >    The third side

                    (a^2+2a)+(2a+3)> a^2+3a+8Rightarrow a> 5     ........(1)

                 (2a+3)+(a^2+3a+8)> a^2+2aRightarrow a> -frac113    ......(2)

          Rightarrow      (a^2+3a+8)+(a^2+2a)> 2a+3

         Rightarrow       2a^2+3a+5> 0  to all  a     	herefore      From (1),(2)   a> 5.

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Deependra Verma

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