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The slope of the line passing through the point (-2,0) and which is tangent to the curve y=x^3 , is

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Solution: Any point on the given curve is (a,a^3) .

             Equation of the tangent at this point is y-a^3=3a^2(x-a).

              This passes through (-2,0) \Rightarrow a=-3

              Hence , the slope `of the tangent 3a^2=27

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Deependra Verma

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