Let "a" be the first term and "d" be the common difference.
It is given that -
aâ‚… + a₉ = 72 and, a₇ + aâ‚â‚‚ = 97
( a + 4d ) + ( a + 8d ) = 72
And ( a + 6d ) + ( a + 11d ) = 97
So,
2a + 12d = 72 -- ( 1 )
2a + 17d = 97 --- ( 2 )
Subtracting ( 1 ) from ( 2 )
5d = 25
d = 5
Put this value of d in ( 1 ) we get :-
2a+60 = 72
2a = 12
a=6
So,
a = 6 and d= 5
Hence, the A.P will be 6,11,16,21........
a5 + a9 = 72
a + 4d + a + 8d = 72
2a + 17d = 72 ---------(1)
a7 + a12 = 97
a + 6d + a + 11d = 97
2a + 17 = 97 ---------(2)
By elimination method we get d = 5,,
2a + 12d = 72
2a + 12(5) = 72
2a + 60 = 72
2a = 72 - 60
2a = 12
a = 12/2
a = 6,,
So,, we get a = 6 & d = 5
a, a + d, a + 2d, a + 3d,.......
6, 6 + 5, 6 + 2(5), 6 + 3(5),.......
6, 11, 16, 21,......
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