Assume three terms in A.P are a-d, a, a+d
a-d+a+a+d = 15
3a =15 => a=5
(a-d)+a2+(a+d) = 93
a2 + d2- 2ad + a2 +a2 + d2 + 2ad = 93
3a2 + 2d2=95
75 + 2d2=95 => d=√10
Hence , the numbers are 5-√10,5, 5+√10.
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