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the total number of positive not exceeding 100 that are divisible by 5 or 7 is

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Solution:    Let  n_1 ,n_2 and n_3 denotethe number of positive

                    integers not exceeding 100 that are divisible by 5,7 and 35.

                Now ,     n_1=[frac1005]=20, n_2=[frac1007]=14

                Rightarrow              n_3=[frac10035]=2

                	herefore      Desired number of numbers =n_1+n_2-n_3=32.

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Deependra Verma

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