The value of definite integral | sinx-cosx| , where lower limit =0 & upper limit =pi/2

Answers (1)

Solution : We have ,

               I=int_0^pi/2left | sin x-cos x 
ight |dx

      \Rightarrow I=int _0^pi/2sqrt2left | sin xcdot cos fracpi4-cos xcdot sinfracpi4 
ight |dx

    \Rightarrow I= int_0^pi/2sqrt2left | sin(x-pi/4) 
ight |dx

         Put ,    x-pi/4=tRightarrow dx=dt

     I=int_frac-pi4^fracpi4sqrt2left | sin t 
ight |dt=2(sqrt2-1)

Most Viewed Questions

Preparation Products

Knockout CUET (Physics, Chemistry and Mathematics)

Complete Study Material based on Class 12th Syllabus, 10000+ Question Bank, Unlimited Chapter-Wise and Subject-Wise Mock Tests, Study Improvement Plan.

₹ 7999/- ₹ 4999/-
Buy Now
Knockout CUET (Physics, Chemistry and Biology)

Complete Study Material based on Class 12th Syllabus, 10000+ Question Bank, Unlimited Chapter-Wise and Subject-Wise Mock Tests, Study Improvement Plan.

₹ 7999/- ₹ 4999/-
Buy Now
Knockout JEE Main (Six Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 9999/- ₹ 8499/-
Buy Now
Knockout JEE Main (Nine Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 13999/- ₹ 12499/-
Buy Now
Knockout NEET (Six Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 9999/- ₹ 8499/-
Buy Now
Boost your Preparation for JEE Main with our Foundation Course
 
Exams
Articles
Questions