The value of the definite integral | sin (x-pi/4) | , where Lower limit =0 & upper limit=pi/2

Answers (1)

Solution: We have ,

                 I=int_0^pi/2left | sin (x-pi/4) 
ight |dx

               Put ,     (x-pi/4)=yRightarrow dx=dy

              Rightarrow I=int_-pi/4^pi/4left | sin y 
ight |dy=int_0^pi/4sin yhspace0.1cmdy=2-sqrt2.

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